{"id":17592,"date":"2024-04-13T09:55:47","date_gmt":"2024-04-13T09:55:47","guid":{"rendered":"https:\/\/soicau4007.minhngocxoso.com\/kinh-nghiem-bat-tong-de-chuan-xac-nhat-2020\/"},"modified":"2024-04-13T09:55:47","modified_gmt":"2024-04-13T09:55:47","slug":"kinh-nghiem-bat-tong-de-chuan-xac-nhat","status":"publish","type":"post","link":"https:\/\/docthuxsmb.com\/kinh-nghiem-bat-tong-de-chuan-xac-nhat\/","title":{"rendered":"kinh nghi\u1ec7m b\u1eaft t\u1ed5ng \u0111\u1ec1 chu\u1ea9n x\u00e1c nh\u1ea5t"},"content":{"rendered":"
\n<\/header>\n

<\/p>\n

\n

C\u00f3 r\u1ea5t nhi\u1ec1u ph\u01b0\u01a1ng ph\u00e1p trong x\u1ed5 s\u1ed1 l\u00f4 \u0111\u1ec1 gi\u00fap anh em ki\u1ebfm b\u1ed9i ti\u1ec1n t\u1eeb c\u00e1c nh\u00e0 c\u00e1i tr\u1ef1c tuy\u1ebfn, m\u1ed9t trong s\u1ed1 \u0111\u00f3 kh\u00f4ng th\u1ec3 kh\u00f4ng k\u1ec3 \u0111\u1ebfn \u0111\u00f3 l\u00e0 kinh nghi\u1ec7m b\u1eaft t\u1ed5ng \u0111\u1ec1 chu\u1ea9n x\u00e1c \u0111\u01b0\u1ee3c m\u00e0 c\u00e1c cao th\u1ee7 trong l\u00e0ng l\u00f4 \u0111\u1ec1 tin d\u00f9ng.<\/span><\/p>\n

Vi\u1ec7c nh\u1edb \u0111\u01b0\u1ee3c c\u00e1c t\u1ed5ng trong l\u00f4 \u0111\u1ec1 s\u1ebd gi\u00fap anh em d\u1ec5 d\u00e0ng t\u00ecm ra c\u00e1c quy lu\u1eadt c\u1ee7a c\u00e1c con s\u1ed1 v\u00e0 n\u1eafm t\u1ef7 l\u1ec7 tr\u00fang r\u1ea5t cao.<\/span><\/p>\n

Tuy nhi\u00ean, \u0111\u1ec3 c\u00f3 th\u1ec3 l\u00e0m \u0111\u01b0\u1ee3c \u0111i\u1ec1u n\u00e0y th\u00ec anh em c\u1ea7n ph\u1ea3i h\u1ecdc h\u1ecfi v\u00e0 tham kh\u1ea3o r\u1ea5t nhi\u1ec1u k\u0129 n\u0103ng t\u1eeb c\u00e1c b\u00e0i vi\u1ebft d\u01b0\u1edbi \u0111\u00e2y\u00a0 nh\u00e9.<\/span><\/p>\n

Nh\u1eefng \u0111i\u1ec1u c\u1ea7n bi\u1ebft v\u1ec1 t\u1ed5ng \u0111\u1ec1<\/span><\/span><\/h2>\n

1. Kh\u00e1i ni\u1ec7m<\/span><\/span><\/h3>\n

T\u1ed5ng \u0111\u1ec1 l\u00e0 m\u1ed9t thu\u1eadt ng\u1eef c\u0169ng kh\u00f4ng xa l\u1ea1 cho l\u1eafm, hi\u1ec3u m\u1ed9t c\u00e1ch \u0111\u01a1n gi\u1ea3n \u0111\u00f3 ch\u00ednh l\u00e0 ph\u00e9p t\u00ednh c\u1ed9ng c\u00e1c con s\u1ed1 trong gi\u1ea3i \u0111\u1eb7c bi\u1ec7t c\u1ee7a ng\u00e0y h\u00f4m tr\u01b0\u1edbc v\u1edbi nhau \u0111\u1ec3 t\u00ecm ra con s\u1ed1 may m\u1eafn cho ng\u00e0y h\u00f4m sau.<\/span><\/p>\n

V\u00ed d\u1ee5: H\u00f4m nay gi\u1ea3i \u0111\u1eb7c bi\u1ec7t v\u1ec1 30985 => \u0111\u1ec1 v\u1ec1 85 => ta c\u00f3 t\u1ed5ng 8 +5 = 13 => tuy nhi\u00ean \u1edf \u0111\u00e2y ch\u1ec9 l\u1ea5y ch\u1eef s\u1ed1 h\u00e0ng ch\u1ee5c v\u00e0 b\u1ecf \u0111i ch\u1eef s\u1ed1 h\u00e0ng \u0111\u01a1n v\u1ecb => t\u1ed5ng \u0111\u1ec1 = 3, t\u01b0\u01a1ng t\u1ef1 v\u1edbi \u0111\u1ec1 v\u1ec1 25 => t\u1ed5ng \u0111\u1ec1 s\u1ebd l\u00e0 2+5 = 7<\/span><\/p>\n

2. T\u1ed5ng h\u1ee3p c\u00e1c lo\u1ea1i t\u1ed5ng \u0111\u1ec1 ph\u1ed5 bi\u1ebfn<\/span><\/span><\/h3>\n

+ T\u1ed5ng \u0111\u1ec1 0<\/span><\/span><\/h4>\n

L\u00e0 bao g\u1ed3m nh\u1eefng con s\u1ed1 c\u00f3 t\u1ed5ng 2 ch\u1eef s\u1ed1 = 0 ho\u1eb7c b\u1eb1ng 10 nh\u01b0 c\u00e1c c\u1eb7p sau \u0111\u00e2y:<\/span><\/p>\n

00 -19 \u2013 91 \u2013 28 \u2013 82 \u2013 37 \u2013 73 \u2013 46 \u2013 64 \u2013 55<\/span><\/p>\n

+ T\u1ed5ng \u0111\u1ec1 1<\/span><\/span><\/h4>\n

L\u00e0 bao g\u1ed3m nh\u1eefng con s\u1ed1 c\u00f3 t\u1ed5ng 2 ch\u1eef s\u1ed1 = 1 ho\u1eb7c = 11, bao g\u1ed3m 10 con s\u1ed1 nh\u01b0 sau:<\/span><\/p>\n

01 \u2013 10 \u2013 29 \u2013 92 \u2013 38 \u2013 83 \u2013 47 \u2013 74 \u2013 56 \u2013 65<\/span><\/p>\n

+ T\u1ed5ng \u0111\u1ec1 2<\/span><\/span><\/h4>\n

L\u00e0 bao g\u1ed3m nh\u1eefng con s\u1ed1 c\u00f3 t\u1ed5ng 2 ch\u1eef s\u1ed1 = 2 ho\u1eb7c = 12, bao g\u1ed3m 10 con s\u1ed1 nh\u01b0 sau:<\/span><\/p>\n

20 \u2013 02 \u2013 39 \u2013 93 \u2013 48 \u2013 84 \u2013 57 \u2013 75 \u2013 66 \u2013 11.<\/span><\/p>\n

+ T\u1ed5ng \u0111\u1ec1 3<\/span><\/span><\/h4>\n

L\u00e0 bao g\u1ed3m nh\u1eefng con s\u1ed1 c\u00f3 t\u1ed5ng 2 ch\u1eef s\u1ed1 = 3 ho\u1eb7c = 13, bao g\u1ed3m 10 con s\u1ed1 nh\u01b0 sau:<\/span><\/p>\n

03 \u2013 30 \u2013 12 \u2013 21 \u2013 49 \u2013 94 \u2013 58 \u2013 85 \u2013 67 \u2013 76.<\/span><\/p>\n

+ T\u1ed5ng \u0111\u1ec1 4<\/span><\/span><\/h4>\n

L\u00e0 bao g\u1ed3m nh\u1eefng con s\u1ed1 c\u00f3 t\u1ed5ng 2 ch\u1eef s\u1ed1 = 4 ho\u1eb7c = 14, bao g\u1ed3m 10 con s\u1ed1 nh\u01b0 sau:<\/span><\/p>\n

04 \u2013 40 \u2013 13 \u2013 31 \u2013 22 \u2013 59 \u2013 95 \u2013 68 \u2013 86 \u2013 77.<\/span><\/p>\n

+ T\u1ed5ng \u0111\u1ec1 5<\/span><\/span><\/h4>\n

L\u00e0 bao g\u1ed3m nh\u1eefng con s\u1ed1 c\u00f3 t\u1ed5ng 2 ch\u1eef s\u1ed1 = 5 ho\u1eb7c = 15, bao g\u1ed3m 10 con s\u1ed1 nh\u01b0 sau:<\/span><\/p>\n

05 \u2013 50 \u2013 14 \u2013 41 \u2013 23 \u2013 32 \u2013 69 \u2013 96 \u2013 78 \u2013 87.<\/span><\/p>\n

+ T\u1ed5ng \u0111\u1ec1 6<\/span><\/span><\/h4>\n

L\u00e0 bao g\u1ed3m nh\u1eefng con s\u1ed1 c\u00f3 t\u1ed5ng 2 ch\u1eef s\u1ed1 = 6 ho\u1eb7c = 16, bao g\u1ed3m 10 con s\u1ed1 nh\u01b0 sau:<\/span><\/p>\n

06 \u2013 60 \u2013 15 \u2013 51 \u2013 24 \u2013 42 \u2013 33 \u2013 79 \u2013 97 \u2013 88.<\/span><\/p>\n

+ T\u1ed5ng \u0111\u1ec1 7<\/span><\/span><\/h4>\n

L\u00e0 bao g\u1ed3m nh\u1eefng con s\u1ed1 c\u00f3 t\u1ed5ng 2 ch\u1eef s\u1ed1 =7 ho\u1eb7c = 17, bao g\u1ed3m 10 con s\u1ed1 nh\u01b0 sau:<\/span><\/p>\n

07 \u2013 70 \u2013 16 \u2013 61 \u2013 25 \u2013 52 \u2013 34 \u2013 43 \u2013 89 \u2013 98.<\/span><\/p>\n

+ T\u1ed5ng \u0111\u1ec1 8<\/span><\/span><\/h4>\n

L\u00e0 bao g\u1ed3m nh\u1eefng con s\u1ed1 c\u00f3 t\u1ed5ng 2 ch\u1eef s\u1ed1 =8 ho\u1eb7c = 18, bao g\u1ed3m 10 con s\u1ed1 nh\u01b0 sau:<\/span><\/p>\n

08 \u2013 80 \u2013 17 \u2013 71 \u2013 26 \u2013 62 \u2013 35 \u2013 53 \u2013 44 \u2013 99.<\/span><\/p>\n

+ T\u1ed5ng \u0111\u1ec1 9<\/span><\/span><\/h4>\n

L\u00e0 bao g\u1ed3m nh\u1eefng con s\u1ed1 c\u00f3 t\u1ed5ng 2 ch\u1eef s\u1ed1 = 9 ho\u1eb7c = 19, bao g\u1ed3m 10 con s\u1ed1 nh\u01b0 sau:<\/span><\/p>\n

09 \u2013 90 \u2013 18 \u2013 81 \u2013 27 \u2013 72 \u2013 36 \u2013 63 \u2013 45 \u2013 54.<\/span><\/p>\n

3. Kinh nghi\u1ec7m b\u1eaft t\u1ed5ng \u0111\u1ec1 chu\u1ea9n x\u00e1c nh\u1ea5t 2024<\/span><\/span><\/h3>\n

1. D\u1ef1a v\u00e0o k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1<\/span><\/span><\/h4>\n

\u0110\u00e2y l\u00e0 m\u1ed9t c\u00e1ch m\u00e0 nhi\u1ec1u cao th\u1ee7 v\u1eadn d\u1ee5ng v\u00e0 \u0111em l\u1ea1i hi\u1ec7u qu\u1ea3 cao. Anh em c\u1ea7n ph\u1ea3i d\u1ef1a v\u00e0o k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 \u0111\u1ec3 t\u00ecm ra \u0111\u01b0\u1ee3c t\u1ed5ng \u0111\u1ec1 c\u00f3 t\u1ef7 l\u1ec7 v\u1ec1 nhi\u1ec1u.<\/span><\/p>\n

C\u00e1ch n\u00e0y c\u0169ng r\u1ea5t \u0111\u01a1n gi\u1ea3n, ch\u1ec9 c\u1ea7n l\u1ea5y 5 con s\u1ed1 trong gi\u1ea3i \u0111\u1eb7c bi\u1ec7t c\u1ed9ng l\u1ea1i v\u1edbi nhau => k\u1ebft qu\u1ea3 t\u00ecm \u0111\u01b0\u1ee3c s\u1ebd ch\u00ednh l\u00e0 con s\u1ed1 c\u1ea7n \u0111\u1ec3 \u0111\u00e1nh cho ng\u00e0y h\u00f4m sau.<\/span><\/p>\n

Ph\u01b0\u01a1ng ph\u00e1p n\u00e0y c\u00f3 t\u1ef7 l\u1ec7 v\u1ec1 \u0111\u1ebfn 85%, do \u0111\u00f3 anh em kh\u00f4ng n\u00ean b\u1ecf qua c\u01a1 h\u1ed9i l\u1edbn nh\u00e9.<\/span><\/p>\n

2. D\u1ef1a v\u00e0o k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1 ng\u00e0y th\u1ee9 2<\/span><\/span><\/h4>\n

V\u1edbi ph\u01b0\u01a1ng ph\u00e1p n\u00e0y, anh em ch\u1ec9 c\u1ea7n ch\u00fa \u00fd \u0111\u1ebfn 2 s\u1ed1 \u0111\u1ea7u trong gi\u1ea3i \u0111\u1eb7c bi\u1ec7t c\u1ee7a ng\u00e0y th\u1ee9 2, \u0111\u1ec3 l\u00e0m t\u1ed5ng \u0111\u1ec1 v\u00e0 \u0111\u1ee3i \u0111\u1ebfn th\u1ee9 4 v\u00e0 th\u1ee9 5 \u0111\u1ec3 \u0111\u00e1nh h\u1ebft tu\u1ea7n.<\/span><\/p>\n

V\u00ed d\u1ee5: K\u1ebft qu\u1ea3 XSMB ng\u00e0y h\u00f4m nay l\u00e0 09468 => 0+ 9+4+6+1 c\u00f3 t\u1ed5ng b\u1eb1ng 0 => do v\u1eady anh em n\u00ean ch\u1ecdn nh\u1eefng con l\u00f4 c\u00f3 t\u1ed5ng 2 ch\u1eef s\u1ed1 b\u1eb1ng 0 \u0111\u1ec3 ch\u01a1i cho tu\u1ea7n sau bao g\u1ed3m nh\u1eefng c\u1eb7p sau: 00 \u2013 19 \u2013 91 \u2013 28 \u2013 82 \u2013 37 \u2013 73 \u2013 46 \u2013 64 \u2013 55.<\/span><\/p>\n

3. D\u1ef1a v\u00e0o ph\u01b0\u01a1ng ph\u00e1p b\u1ea1c nh\u1edb<\/span><\/span><\/h4>\n

Anh em c\u00f3 th\u1ec3 tham kh\u1ea3o theo b\u1ea3ng d\u01b0\u1edbi \u0111\u00e2y:<\/span><\/p>\n